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Home » 15^2 = 225 > 200 \quad \text(not valid) - Feedz API

15^2 = 225 > 200 \quad \text(not valid) - Feedz API

📅 May 16, 2026 👤 scraface

May 16, 2026

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📌 Let \( x = \sin \theta \), so:

📌 2x^2 + x - 1 = 0

📌 x = \frac{-1 \pm \sqrt{1^2 - 4(2)(-1)}}{2(2)} = \frac{-1 \pm \sqrt{1 + 8}}{4} = \frac{-1 \pm 3}{4}

📌 This gives:

📌 x = \frac{2}{4} = \frac{1}{2} \quad \text{or} \quad x = \frac{-4}{4} = -1

📌 So, \( \sin \theta = \frac{1}{2} \) or \( \sin \theta = -1 \).

📌 Solve for \( \theta \in [0^\circ, 360^\circ] \):

📌 If \( \sin \theta = \frac{1}{2} \), then \( \theta = 30^\circ, 150^\circ \)

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