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a + b + c - \log\left( rac{x}{z} + rac{z}{x}
ight) = a + b + c - \log\left( rac{1}{b} + b
since $ rac{x}{z} = rac{x}{y} \cdot rac{y}{z} = ac = rac{1}{b} $, and similarly $ rac{z}{x} = rac{1}{c} $, but $ rac{x}{z} + rac{z}{x} = b + rac{1}{b} $.

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