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Home » \frac{A_{\textcircle}}{A_{\texttriangle}} = \frac25\pi150 = \frac\pi6 - Feedz API

\frac{A_{\textcircle}}{A_{\texttriangle}} = \frac25\pi150 = \frac\pi6 - Feedz API

📅 May 18, 2026 👤 scraface

May 18, 2026

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📌 Letâs use the roots of \( u^2 - 2u + 2 = 0 \). The discriminant is \( 4 - 8 = -4 \), so roots are:

📌 u = rac{2 \pm \sqrt{-4}}{2} = rac{2 \pm 2i}{2} = 1 \pm i

📌 Let \( lpha = 1 + i \), \( eta = 1 - i \). Then at \( u = lpha \):

📌 lpha^4 + 3 = alpha + b

📌 First compute \( lpha^2 \):

📌 lpha = 1 + i \Rightarrow lpha^2 = (1+i)^2 = 1 + 2i + i^2 = 1 + 2i - 1 = 2i

📌 lpha^4 = (lpha^2)^2 = (2i)^2 = 4i^2 = -4

📌 lpha^4 + 3 = -4 + 3 = -1 = a(1+i) + b = a + ai + b

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