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📅 May 18, 2026 👤 scraface

May 18, 2026

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Thus, the probability is \(\boxed{\frac{1}{2}}\).
Question:** The average of \( 3v+2 \), \( 5v-1 \), and \( 4v+7 \) is r...
First, compute the average of the three expressions:
\text{Average} = \frac{(3v+2) + (5v-1) + (4v+7)}{3} = \frac{12v + 8}{3...
We require this average to be less than 25:
4v + \frac{8}{3} < 25
Subtract \(\frac{8}{3}\) from both sides:
4v < 25 - \frac{8}{3} = \frac{75}{3} - \frac{8}{3} = \frac{67}{3}
Now divide by 4:
v < \frac{67}{12} \approx 5.583

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