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📰 So only **one** way to place 3 non-adjacent G’s in 5 specific positions — only if they are in positions that can be mapped to {1,2,3,4,5} with gaps.
📰 But it’s only possible if the 5 positions allow a 3-element non-adjacent subset — which requires that the positions span at least 5 positions (e.g., 1,3,5), and in any 5 consecutive positions, there is exactly **one** such set? Not quite — for positions {1,2,3,4,5}, non-adjacent triples: 1,3,5 only? But 1,4,5 has adjacent, 2,4,5 has adjacent. Yes, only {1,3,5} if starting at 1, but depending on layout.
📰 Actually, the number is not always 1. For example, {1,3,4} has adjacent 3-4, invalid. So only triples with min gap 2.
