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Home » Thus, the sum is \( \boxed0 \). - Feedz API

Thus, the sum is \( \boxed0 \). - Feedz API

📅 May 16, 2026 👤 scraface

May 16, 2026

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Rearrange: \( xy - 2y = x + 3 \).
Factor: \( y(x - 2) = x + 3 \).
Solve for \( y \): \( y = rac{x + 3}{x - 2} \).
#### Inverse: \( f^{-1}(x) = rac{x + 3}{x - 2} \)
Evaluate the limit \( \lim_{x o 2} rac{x^2 - 4}{x - 2} \).
Factor the numerator: \( x^2 - 4 = (x - 2)(x + 2) \).
The expression becomes \( rac{(x - 2)(x + 2)}{x - 2} \).
Cancel \( x - 2 \) (for \( x
eq 2 \)): \( x + 2 \).
Thus, \( \lim_{x o 2} (x + 2) = 4 \).

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